Array Join
From SwiftAPI
(Redirected from JavaScript Array.join)
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C#
string[] a = {"9", "4", "0", "4", "0"}; string s = "."; string r = String.Join(s, a); // r == "9.4.0.4.0"
JavaScript
var a = [9, 4, 0, 4, 0]; var s = '.'; var r = a.join(s); // r == '9.4.0.4.0'
Objective-C
- (NSString *)componentsJoinedByString:(NSString *)separator
NSArray *a = @[@"9", @"4", @"0", @"4", @"0"]; NSString *s = @"."; NSString *r = [a componentsJoinedByString:s]; // r == "9.4.0.4.0"
Perl
join EXPR,LIST
@a = (9, 4, 0, 4, 0); $s = '.'; $r = join($s, @a); # $r == '9.4.0.4.0';
PHP
string implode ( string $glue , array $pieces ) string implode ( array $pieces )
$a = array(9, 4, 0, 4, 0); $s = '.'; $r = implode($s, $a); // $r == '9.4.0.4.0'
Python
a = [9, 4, 0, 4, 0] s = '.' r = s.join(a) # r == '9.4.0.4.0'
Ruby
a = [9, 4, 0, 4, 0] s = '.' r = a.join(s) # r == '9.4.0.4.0'
Swift
let a = ["9", "4", "0", "4", "0"] let s = "." let r = join(s, a) // r == "9.4.0.4.0"